will npm download the newest subversion by default?(support needed)

[appleyuchi]

apologise that copy node-sass's official hints into following table

version name	command	my version
NPM version	npm -v	6.11.3
Node version	node -v	v12.11.1
Node Process	node -p process.versions	node: '12.11.1', v8: '7.7.299.11-node.12', uv: '1.32.0', zlib: '1.2.11', brotli: '1.0.7', ares: '1.15.0', modules: '72', nghttp2: '1.39.2', napi: '5', llhttp: '1.1.4', http_parser: '2.8.0', openssl: '1.1.1c', cldr: '35.1', icu: '64.2', tz: '2019a', unicode: '12.1'
Node Platform	node -p process.platform	linux
Node architecture	node -p process.arch	x64
node-sass version	node -p "require('node-sass').info"	node-sass 4.14.1 (Wrapper)[JavaScript] libsass 3.5.5 (Sass Compiler) [C/C++]
npm node-sass versions	npm ls node-sass	appleyuchi@1.0.0 /home/appleyuchi └── node-sass@4.14.1

package.json is:
https://paste.ubuntu.com/p/7QNx7qPjrr/

My question is :
why did npm cichoose linux-x64-72_binding.node which has been deleted in the following link?
#2648

I mean,why the 72above is selected?
just newest by default or set by somewhere?

aplogise that if github is not the right place to ask question,
point this to me please and I'll ask it on quora/stackoverflow,etc...

[xzyfer]

72 is V8 module version for node 12. See the table at the top of the readme.