Solution #14 - Daniel/Edited - 16.03.2025 - #36
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Kindly make the requested changes and do the same for the other PR's as well
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| ### 1. Lexicographic Sorting | ||
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| 1. Lexicographically sorting the array | ||
| 2. Comparing the first and last of the sorted array for prefix. | ||
| 3. Create an empty string called prefix. | ||
| 4. Iteratively, go through the characters to add matching characters to the prefix string. | ||
| 5. When there is a mismatch, end the loop and return the prefix string. | ||
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| - Since we are lexicographically sorting the array, the first and last string are the most different. Finding the common prefix between the two, would be the longest common prefix for all the strings in the array between them. | ||
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| #### Time Complexity | ||
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| O(nlogn) because we sort the array, traversing the two strings will be done in O(n) time which is overshadowed by the worser time complexity O(nlogn). |
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Much better! Kindly add the solutions corresponding to the explanation as well into the cpp file
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Kindly add the solutions corresponding to the explanation as well into the cpp file
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Solution and Explanation uploaded