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Copy pathfind-peak-element.cpp
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49 lines (46 loc) · 1.22 KB
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// A peak element is an element that is greater than its neighbors.
//
// Given an input array nums, where nums[i] ≠ nums[i+1], find a peak element and return its index.
//
// The array may contain multiple peaks, in that case return the index to any one of the peaks is fine.
//
// You may imagine that nums[-1] = nums[n] = -∞.
//
// Example 1:
//
//
// Input: nums = [1,2,3,1]
// Output: 2
// Explanation: 3 is a peak element and your function should return the index number 2.
//
// Example 2:
//
//
// Input: nums = [1,2,1,3,5,6,4]
// Output: 1 or 5
// Explanation: Your function can return either index number 1 where the peak element is 2,
// or index number 5 where the peak element is 6.
//
//
// Note:
//
// Your solution should be in logarithmic complexity.
//
class Solution {
public:
int findPeakElement(vector<int>& nums) {
int len = nums.size();
if (len < 2) return len-1;
int low = 0, high = len-1;
while (low < high) {
int mid1 = (low+high)/2;
int mid2 = mid1 + 1;
if (nums[mid1] > nums[mid2]) {
high = mid1;
} else {
low = mid2;
}
}
return low;
}
};