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refactor: unwrap ConfigSkills namespace + self-reexport (#22950)
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import z from "zod"
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export namespace ConfigSkills {
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export const Info = z.object({
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paths: z.array(z.string()).optional().describe("Additional paths to skill folders"),
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urls: z
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.array(z.string())
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.optional()
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.describe("URLs to fetch skills from (e.g., https://example.com/.well-known/skills/)"),
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})
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export const Info = z.object({
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paths: z.array(z.string()).optional().describe("Additional paths to skill folders"),
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urls: z
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.array(z.string())
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.optional()
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.describe("URLs to fetch skills from (e.g., https://example.com/.well-known/skills/)"),
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})
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export type Info = z.infer<typeof Info>
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}
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export type Info = z.infer<typeof Info>
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export * as ConfigSkills from "./skills"

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