-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy pathLeetcode Problem 141 Linked List Cycle.txt
More file actions
62 lines (50 loc) · 1.47 KB
/
Leetcode Problem 141 Linked List Cycle.txt
File metadata and controls
62 lines (50 loc) · 1.47 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
Leetcode Problem 141 Linked List Cycle
Description :
Given a linked list, determine if it has a cycle in it.
To represent a cycle in the given linked list, we use an integer pos which represents the position (0-indexed) in the linked list where tail connects to.
If pos is -1, then there is no cycle in the linked list.
Example 1:
Input: head = [3,2,0,-4], pos = 1
Output: true
Explanation: There is a cycle in the linked list, where tail connects to the second node.
Example 2:
Input: head = [1,2], pos = 0
Output: true
Explanation: There is a cycle in the linked list, where tail connects to the first node.
Example 3:
Input: head = [1], pos = -1
Output: false
Explanation: There is no cycle in the linked list.
Hint to solve: use rabbit and tortoise method. 2 pointers.
Language: C#
Solution:
/**
* Definition for singly-linked list.
* public class ListNode {
* public int val;
* public ListNode next;
* public ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public bool HasCycle(ListNode head)
{
if(head == null)
return false;
ListNode tortoise = head;
ListNode rabbit = head.next;
while(rabbit != null && rabbit.next != null)
{
tortoise = tortoise.next;
rabbit = rabbit.next.next;
if(tortoise == rabbit)
{
return true;
}
}
return false;
}
}