Problem 6 / Challenge #6: Sum Square Difference
The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385.
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025.
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
ProjectEuler+ Problem Statement
The Project Euler problem is equivalent to the ProjectEuler+ challenge with T = 1 and N = 100.